Ask a Question

Get a Fast and Accurate Answer to your Question

Share Question

What is the electron configuration of lead?

Class-12 Biology

Asked By Raj Kapoor

4 Answers

  • Mehak Rajput

    The atomic NUMBER for lead is 82.

    Therefore the electronic configuration for Pb is

    [Xe]4f14,5d10,6s2,6p2
  • Radhika Sharma

    The electronic configuration for Xe is

    1s2,2s2,2p6,3s2,3p6,3d10,4s2,4p6,4d10,...



    Therefore the electronic configuration for Pb is actually

    1s2,2s2,2p6,3s2,3p6,3d10,4s2,4p6,4d10
  • Keshav Sharma

    [Xe] 4f14 5d10 6s2 6p2
  • Radhika Sharma

    write the sublevels up to where you will have up to 82 electrons:
    1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^2, 3d^10, 4p^6, 5s^2, 4d^10, 5p^6, 6s^2, 4f^14, 5d^10, 6p^2

    Okay now gather all the exponents and add to see if you get 82 electrons (expoenents represent the number of electrons in each sublevel):
    2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 + 6 + 2 + 14 + 10 + 2 = 82

Ask your own question. Don't worry, it's completely free!

Live Chat Software