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    What is the electron configuration of lead?

    Class-12 Biology

    Asked By Raj Kapoor

    4 ANSWERS

    • The atomic NUMBER for lead is 82.

      Therefore the electronic configuration for Pb is

      [Xe]4f14,5d10,6s2,6p2
    • The electronic configuration for Xe is

      1s2,2s2,2p6,3s2,3p6,3d10,4s2,4p6,4d10,...



      Therefore the electronic configuration for Pb is actually

      1s2,2s2,2p6,3s2,3p6,3d10,4s2,4p6,4d10
    • [Xe] 4f14 5d10 6s2 6p2
    • write the sublevels up to where you will have up to 82 electrons:
      1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^2, 3d^10, 4p^6, 5s^2, 4d^10, 5p^6, 6s^2, 4f^14, 5d^10, 6p^2

      Okay now gather all the exponents and add to see if you get 82 electrons (expoenents represent the number of electrons in each sublevel):
      2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 + 6 + 2 + 14 + 10 + 2 = 82

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